How to Calculate (BBS) Bar Bending Schedule Estimate of Steel in High Rise Building/STP/Bridge Construction?
Introduction to Bar Bending
Schedule (BBS): -
“BBS” The word BBS Plays a significant role in any construction
of High-rise buildings. BBS refers to Bar Bending Schedule. Well, What’s the
use of BBS? Why we use BBS? What is BBS?
In this article, we are majorly focused on how and where to
start and what are the basics. Apart from this, you can also learn
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§ What is Bar Bending Schedule?
and its Importance
§ Basics of Bar Bending Schedule?
§ How to Prepare Bar Bending
Schedule?
§ Important rules while preparing
Bar Bending Schedule
§ Use of Bar Bending Schedule?
It’s a lengthy article, so brace yourself for at least 10
minutes. Let’s Get started.
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First, Bar is any type of rebar which is used as a reinforcement in
RCC. The bar may be a Mild Steel bar or HYSD bar or TMT Bar.
Bar Bending Schedule
is termed as “Calculation of the total Steel required for the construction of a
building” We use steel to make concrete to be reinforced and for tension
requirements. But how much steel required for constructing 15 floors building?
How much Steel I must order? All these questions are answered in BBS
In Bar bending schedule, the bars are organized for each
structural units (Beams or columns or slabs or footings etc) and detailed list
is prepared which specifies the Bar location (Bar in footings, slabs,
beams or columns), Bar Marking (to identify the bar in accordance with the
drawing), Bar Size (length of the bar used), Quantity (No. of Bars used),
Cutting length, Type of Bend and Shape of the bar in reinforcement
drawings.
How BBS Changed from 1950-2019: -
From 1950 to 2019 lots
of modifications and enhancements happening in our world. In 1950,
three-stored buildings are high rise buildings now we are constructing a
building with 200 floors+. There is a massive growth in the construction
industry. Due to the vast increase in world population demands increased
facilities, more need for space and more construction.
Father of Estimation B.N. Datta has given certain recommendations for the usage of steel
in different components of buildings. But he didn’t mention any values if we
use more bars in a single structural member.
Bar Bending Member
|
Percentage
|
Slab
|
1% of total volume of concrete
|
Beam
|
2% of total volume of concrete
|
Column
|
2.5% of total volume of concrete
|
Footings
|
0.8% of total volume of concrete
|
At that time we’ve used only four bars in columns; now we are using 12+
bars in columns based on load analysis. So, the percentage
of steel is increased in a column which reveals that the above-cited values are
outdated. (They are outdated “not wrong”) He wrote that book in 1950. Now we
are in 2019. He gave recommendations according to the potentiality of
construction at that time. Now we are constructing 200 + floors in the small
area.
Bar Bending Schedule [BBS]: -
Before dealing with the BBS, it’s very important to learn the
basics of Bar bending schedule. The below-mentioned table is a quick-start
guide for learning Bar bending schedule from scratch.
(If you are viewing the below table through mobile, scroll horizontally
for a clear view)
S.No.
|
Particulars
|
Result
|
1.
|
Standard
Length of the Steel Bar
(Bars are sold at standard Length) |
12m or
40'
|
2.
|
Weight of
Bar
for length = 1m |
D2/162
(were D = Dia of Bar) |
Ex:
|
If length
of bar is 12m with 10mm Día then,
Weight of bar = D2/162 Therefore for length 1m = 1m x D2/162 = 1 x 102/162 = 0.61 Kgs For length 12m = 12 x 102/162 = 7.40Kgs |
7.40Kgs
|
3.
|
Density
of Steel
|
7850Kg/m3
|
1. Hook Length or Cutting length of Stirrups: -
The hook length is
commonly provided for stirrups in beams and ties in columns. In general, Hooks are
added at the two ends of the rebar in stirrups or ties.
Hook Length = 9d (d is dia of the bar)
Below image makes you clear why the Hook length = 9d
From above fig, length of hook = [(Curved Portion) + 4d] =
[(4d+d)+4d] = 9d
Hook Length = 9d [d is Diameter
of the Bar]
Example
Calculation considering stirrup with the hooks at ends:
For clear understanding, look at the below image for calculation
of the total length of stirrup the with two hooks at ends.
Total Cutting Length of stirrup or tie = Total length of Bar + 2
x Hook Length (Two hooks)
Total Cutting Length = L+2(9d)
Therefore, Total Cutting length = L+18d (d is the Diameter of a
bar)
Hope, now you are clear with the Hook length calculation.
2. Bend Length: -
The Bend length calculation
is different for Cranked bars (bent up bars) and bends at corners.
The bars are usually
cranked in Slabs and bars are bent at corners in Stirrups or ties.
(i) Bend Length calculation in Cranked Bars: -
As Shear stress
is maximum at supports in Slab. To resist these stresses, we usually crank the
bars at the ends of supports in the slab. The below figure depicts the bent-up
bar in Slab. To calculate the bend length the below procedure is followed.
From
the above figure as the bar is bent at an angle θ0 the additional
length (la) is introduced.
Where,
la = l1 – l2–(i)
Tanθ = D/l2 ; Sinθ = D/l1
Hence
l1 = D/Sinθ and l2 = D/tanθ
Therefore
from (i) :- la = D/Sinθ – D/tanθ
Giving
different θ values as 300 , 450, 600 results different
additional length la values as below.
θ0
|
D/Sinθ
|
D/tanθ
|
la =D/Sinθ – D/tanθ
|
300
|
D/0.500
|
D/0.573
|
0.27D
|
450
|
D/0.707
|
D/1.000
|
0.42D
|
600
|
D/0.866
|
D/1.732
|
0.58D
|
900
|
D/1
|
0
|
1D
|
1350
|
D/0.707
|
D/-1
|
2.42D
|
The additional length is added to the total length of the
bar if the bars are cranked at a certain angle.
Example
Calculation considering Bent up bar in Slab (Cranked bar): -
To keep the crank bar in position, an extra bar of length (L/4)
is provided below the crank bar as shown in the below figure.
Therefore, the total length of bar = L+0.42D+0.42D+(L/4) +(L/4)
= 1.5L+0.84D
Remember D = Depth of Slab-Top Cover-Bottom cover
(ii) Bend Length calculation when bars are bent at corners:-
The important standards used while calculating the bend length
at corners
1.
45° Bend length = 1d
2.
90° Bend length = 2d
3.
135° Bend length = 3d
Here, ‘d’ = Diameter of bar
Example
Calculation considering stirrup with the bends at corners:
From
above fig, There are 3 bends which are bent at an angle of 900 and two bends
are bent at an angle of 1350
Total bend length = 3 x 900 Bend length + 2 x 1350 Bend length = 3
x 2d + 2 x 3d = 12d = 12 x 8 = 96mm
Below
table represents the total length of bar calculation for different types of bar
shapes.
(If you are viewing the below table through mobile, scroll horizontally for a clear view)
(If you are viewing the below table through mobile, scroll horizontally for a clear view)
Bar Shapes
|
Total Length of Hooks
|
Total Bend Length
|
Total Length of Bar
|
Straight
Bar
|
Two Hooks
= 9d + 9d = 18d |
No bend
|
l + 18D
|
Bent
Up at one End only
|
Two Hooks
= 9d + 9d = 18d |
One bend
bent at an angle 45 = 0.42D |
l + 18D +
0.42D
|
Double
Bent up Bar
|
Two Hooks
= 9d + 9d = 18d |
Two bends
bent at an angle 450 |
l + 18D +
0.42D + 0.42D
=l+18D+0.84D |
Overlap
of bars
|
Two Hooks
= 9d + 9d = 18d |
No bends
|
Overlap
Length
= (40d to 45d)+18d |
3. Overlap Length / Lap Length in Reinforcement: -
The standard length of
Rebar is 12m. Suppose the height of the column is 20 m. To purvey this
requirement, two bars of length 12m and 8m are overlapped (joined) with overlap
length.
Overlap Length for compression members
(columns) = 50d
The Overlap Length for tension members (beams)
= 40d
[d is the Diameter of the bar]
Have You seen the
below picture on your top floor of the building? We generally project some
length of Bar on the last floor i.e., 50D. It is used for further construction
purpose. (Constructing a new floor)
Also Read: Development
length in Bar Bending Schedule
How to Prepare Bar Bending Schedule:
To understand clear, Here I am considering the below structural
member RCC Column and preparing a BBS for it.
BBS of Column
|
|
Structural Member
|
Column
(3mx0.3mx0.3m) |
Bar Marking
|
1. Main Bars
2. Stirrups (Longitudinal bars) |
Dia of Bar
|
1. Main Bars = 16mm;
2. Stirrups (Longitudinal bars) = 8mm |
No. of Bars used
|
1. Main bars = 4
2. Stirrups = 30 |
Cutting length
|
1. Main bars = 3.16m
2. Stirrups = 2.64m |
Total Length of bar
|
1. Main bars = 18.4m
2. Stirrups = 43.2m |
Weight of Steel bar
|
1. Main bars = 29Kgs
2. Stirrups =17Kgs |
Calculation
part of above table:
No.
of Bars calculation:
Main bars = 4
To calculate the No. of longitudinal bars adopt spacing between bars is 0.1m
No. of Longitudinal bars = Length of column / Spacing = 3/0.1 = 30bars
Longitudinal bars = 30
Main bars = 4
To calculate the No. of longitudinal bars adopt spacing between bars is 0.1m
No. of Longitudinal bars = Length of column / Spacing = 3/0.1 = 30bars
Longitudinal bars = 30
Cutting
length calculation:
Main bars = 3m + 50d + 50d = 3 + 50×0.016 + 50×0.016 = 4.6m
Stirrups:
Hook length = 9d + 9d = 18d = 18×0.08=1.44m
Bend length =3 x 900 Bend length + 2 x 1350 Bend length
= 3 x 2d + 2 x 3d = 12d = 12 x 8 =0.096m
Main bars = 3m + 50d + 50d = 3 + 50×0.016 + 50×0.016 = 4.6m
Stirrups:
Hook length = 9d + 9d = 18d = 18×0.08=1.44m
Bend length =3 x 900 Bend length + 2 x 1350 Bend length
= 3 x 2d + 2 x 3d = 12d = 12 x 8 =0.096m
= l +hook length + bend length = 0.3+0.3+0.3+0.3
+0.144+0.096=1.44m
Hence for Main Bars = 4.6m; Longitudinal bars = 1.44m
Total
Length of Bars:
Total length of Main bars = No. of Main bars x length of one bar
= 4 x 4.6 = 18.4m
Total length of Longitudinal bars=No. of longitudinal bars x length of one bar
=30×1.44=43.2m
Total length of Main bars = No. of Main bars x length of one bar
= 4 x 4.6 = 18.4m
Total length of Longitudinal bars=No. of longitudinal bars x length of one bar
=30×1.44=43.2m
Weight
of steel bar:
Weight of steel bar for 1m = 1m x D2/162
Total weight of Main bars = 18.4 x 162/162 = 29Kgs
Total weight of longitudinal bars = 43.2 x 82/162 =17Kgs
Weight of steel bar for 1m = 1m x D2/162
Total weight of Main bars = 18.4 x 162/162 = 29Kgs
Total weight of longitudinal bars = 43.2 x 82/162 =17Kgs
Total
weight of steel bar required to do BBS of above column = 46Kgs
Important rules while preparing Bar Bending Schedule: -
§ The bars used in
building should be grouped together for each structural unit and listed separately
for each floor.
§ Bars are listed in
numerical order.
§ To identify the bar in
the bundle of bars, each bar is uniquely labelled with reference details
(Length of the bar, size of the bar, Shape of the bar)
§ The type of bar and
shape of the bar should be in accordance with B8666.
§ It is essential that
the bar mark reference on the label attached to a bundle of bars
refers uniquely to a particular group or set of bars of defined length, size,
shape and type used on the job.
§ The cutting length and
bending length calculations are separately calculated and not included in the
detailed list. Like I have listed the Bar Bending details in a table and
calculations are done separately.
Use of Bar Bending Schedule:
§ BBS helps to estimate
the total quantity of steel required for the construction of building or structure.
It helps to quote for tender the cost incurred by steel.
§ Finding the cutting
length and bending length in reinforcement detailing improves the quality of
construction and minimize the wastage of steel, makes an economic construction
§ With the help of
reinforcement drawings, cutting and bending can be done at the factory and
transported to the site. This increases faster construction and reduces the
total construction cost.
§ For site engineers, it
becomes easy to verify the cutting length and bending length of the
reinforcement before placing the concrete.
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